Key Concepts & Self-Assessment15 Key Facts
Review key Gravitation & Kepler Laws: Orbital Dynamics, Satellite Orbits & Gravity exam facts and rate your mastery to track revision.
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#1
Newton's universal law of gravitation states that gravitational attraction between two point masses is directly proportional to their product and inversely proportional to distance squared.
#2
The universal gravitational constant G equals 6.67430 × 10^-11 N·m^2/kg^2 and represents a universal physical constant independent of intervening medium.
#3
Henry Cavendish measured the numerical value of G in 1798 using a sensitive torsion balance apparatus, which also enabled calculating Earth's mean density.
#4
Acceleration due to gravity at Earth's surface follows g = GM/R^2, possessing a standard reference value of 9.80665 meters per second squared.
#5
The value of g is maximum at the poles (approx 9.83 m/s^2) and minimum at the equator (approx 9.78 m/s^2) due to equatorial bulge and diurnal rotation.
#6
Acceleration due to gravity decreases with increasing altitude above the surface according to g_h = g(1 - 2h/R) for altitudes much smaller than Earth's radius.
#7
Below Earth's surface, gravitational acceleration decreases linearly with depth according to g_d = g(1 - d/R), becoming zero at Earth's geometric center.
#8
Kepler's First Law (Law of Ellipses) states that all planets move in elliptical orbits with the Sun situated at one of the two foci.
#9
Kepler's Second Law (Law of Equal Areas) establishes that a line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.
#10
Kepler's Second Law represents a direct physical consequence of the conservation of angular momentum under a central gravitational force.
#11
Kepler's Third Law (Harmonic Law) states that the square of the orbital period T is directly proportional to the cube of the semi-major axis a (T^2 ∝ a^3).
#12
Orbital velocity for a satellite in low Earth circular orbit equals approximately 7.92 km/s, governed by equating gravitational force to centripetal force.
#13
Escape velocity from a celestial body is calculated via ve = √(2GM/R) = √(2) * vo, equaling approximately 11.2 km/s for Earth and 2.38 km/s for the Moon.
#14
Geostationary satellites orbit at an altitude of 35,786 kilometers directly above the equator, completing one revolution in 23 hours, 56 minutes, and 4 seconds.
#15
Polar satellites operate in Sun-synchronous low Earth orbits at altitudes of 600 to 800 kilometers, completing north-south passes useful for remote sensing.
Subject Specialist Commentary
Analytical perspective & practical exam advice from the Master10 academic board
Gravitation is the universal attractive force that governs everything from falling apples to planetary orbits. Formulated by Isaac Newton and measured by Henry Cavendish, gravity depends directly on interacting masses and weakens with distance squared. In our solar system, Kepler's laws explain how planets travel along ellipses, sweeping out equal areas in equal times due to angular momentum conservation, with farther planets taking predictably longer periods to complete their cosmic journeys.
In SSC and UPSC general science questions, variations in 'g' and satellite dynamics are common traps. Remember that acceleration due to gravity is highest at the poles and lowest at the equator, dropping to zero at Earth's center. Do not confuse escape velocity (roughly 11.2 km/s on Earth) with orbital velocity (around 7.9 km/s). For exam revision, keep in mind that geostationary satellites hover at 35,786 kilometers directly over the equator.
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